Diammonium phosphate (DAP) contain 46% Phosphorus. How much DAP should be needed to prepare 1% Phosphorus solution ?
Dear Imadud Din you need 2.17g of DAP (46%).
Method: 1% defined as 1g of Phosphorus per 100ml of solution and 46% defined as 100g of DAP contains 46g of Phosphorus.
100g of DAP→46g of P
Xg of DAP →1g of P
X=100x1/46=2.17g.
Chemical Properties Chemical formula: (NH4)2HPO4 Composition:
18% N, 46% P2O5, (20% P).
You must to know how much the percent of P IN P2O5.
100g P2O5 → 43g P
x → 1g P(this value you need to have in DPA).
2.32g of P2O5 have 1 g of P
Then
100g DPA → 46 g P2O5
x → 2.32g
Now you must add 5.04 g of DPA to get 1g P.
DAP contains 46 % P2O5 and not P.
It contains 20.07 % P.
Amount of P in P2O5 is 2.29
Thus for 20.07 g P you add 100 g DAP
For 1 % P add 4.982 g DAP or ~ 5.0 g DAP
1% Phosphorus solution contains 1 g of Phosphorus per 100 g of water solution.
46 g of P are in 100 g of DAP --
1g of P are in X g of DAP
x = 2,17 g
For preparation of 100 g of 1% Phosphorus solution you need to take 2,17g of DAP and to add 97,83 g of water.
Dear Ovsiannikova Svetlana ,
But there are two sources for P in DAP.
P20%
P2O5 46%
DAP contain 46% P2O5 not 46%P
you can to change the P2O5% to P% by the equation below
P% = P2O5% x 0.44
P%= 46 x 0.44 = 20.24%
for 1% P = 100/20.24 = 4.94 g
or add 4.94 g of DAP in 100ml D.W. to prepare 1% P
Bcecause DAP contain 46% P2O5 and you want to change it to P%
the Molar mass of P = 30.973761 g/mol it means
Molar mass of P2O5 = (30.973761x2) +(16x5)=61.94752 + 80= 141.94752 g /mol of P2O5
the P2O5 contain 2 mol P to change P2O5 to P in shoulbe divide
(30.973761x2) /141.94752= 61.94752 /141.94752 = 0.4364 or =0.44
or 0.44 is a factor to change P2O5% to P%
If DAP contain 46% P2O5, I agree with Ghafoor Ahmed Mam Rasul.
I have already worked on DAP as an inhibitor of scaling, and I agree with Ghafoor Ahmed Mam Rasul
Conference Paper Etude comparative de trois engrais de synthèse à base de pho...
https://www.researchgate.net/deref/http%3A%2F%2Fdx.doi.org%2F10.4236%2Fjwarp.2015.715100
The DAP contains 46%P2O5 and with the conversion factor of 0.44 it turns out to be 20.2%P. And the you proceed to dilution to bring the 20.2% to 1%.
so for 1Liter you must get 10gP. remember 10gP represents 20.2% of the total DAP so yiu need 49.5g DAP to obtain 1%P solution.
Dear Huma, Molar mass of DAP is 132.06 and molar mass of P is 30.974. Amount of DAP required to make 1g P per liter = 132.06/30.974= 4.26 g If u dissolve 4.26 g in 1 L deionized water, it will be 1000 ppm solution of P and if 0.426g DAP is dissolved in deionized water and volume is made to 1 L, it will give u 100 ppm solution of P.
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