Hanwu Yang
Of course it is possible to use the Taylor series you mentioned, but it is not very efficient.
Wikipedia lists several other infinite series which converge faster: https://en.wikipedia.org/wiki/Logarithm
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Prasanta Roy
@Hanwu Yang: this are in terms of (1+x) or (1-x) . Is it possible in terms of power of x such as log(x)=a0+a1x+a2x^2+---------
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Hanwu Yang
I consider it not possible, at least for real number of x - but I am not expert on Mathematics.
If it is possible then Sum(a0,a1,a2,...)=0, because at x=1 log(x)=0;
but a0 is not well defined, as at x=0, log(0)=-infinite.
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