in what solvent 0.1 M perchloric acid is prepared deionized water or glacial acetic acid??
Dear Zaid,
Take about 500 ml of anhydrous glacial acetic acid and about 25 ml acetic anhydride in a cleaned and dried 1000 ml volumetric flask. Add about 8.5 ml of Perchloric acid (About 70%) with continues stirring. Cool the solution. Make up the volume 1000ml with anhydrous glacial acid. Mix solution thoroughly. Keep the solution for at least 24 hours for the excess acetic anhydride to be combined. Then carry out the determination of water. If the water content exceeds 0.05% add more acetic anhydride. If the solution contains water, add sufficient water to obtain a content of water between 0.02% to 0.05%. Allow the solution to stand for 1 day and again titrate the water content. The solution so obtained should contain between 0.02% and 0.05% of water. Standardize the solution.
With my best regards
Prof. Bachir ACHOUR
You can see the linked files for your better understanding and procedure.
http://www.pharmaguideline.com/2011/03/preparation-and-standardization-of-01-m.html
http://www.sigmaaldrich.com/catalog/product/saj/241060?lang=en®ion=US
How do i prepare 0.010M or 0.005M of perchloric acid from 0.1M perchloric acid? Should i use water or acetic acid or glacial acetic acid for dilution? Can any answer me???
Dear Mahalaxmi
it is depend upon your choice of vehicle used for making stock solution of perchloric acid.
In glacial acetic acid.
1. 0.1 N Perchloric acid in glacial acetic acid
Calculation for making 100 ml of 0.1 N perchloric acid solution:
1000 ml of 1 N HClO4=100 g/eq of HClO4
100 ml of 0.1 N HClO4= 100 x 100 x 0.1
1000
= 1.0 g of HClO4
Density= Mass
Volume
Volume=Mass 1.0 g = 0.59 ml of HClO4
Density 1.7 g/ml
Since the purity of HClO4 is 70 %
Therefore, 70 % = 0.59 ml
100 % = 0.59 x 100 = 0.84 ml
70
Hence, measure accurately about 0.84 ml of HClO4, dissolve in 70 ml of glacial acetic acid. Add 3 ml of acetic anhydride, cool and make up the volume to 100 ml with glacial acetic acid.
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