I have digested 100 mg of bone ash in HNO³ 95% 3 ml and HCL 37% 0.5 ml and diluted upto 60 ml. After analysis on ICP-MS the answer is 9192.358 ppm of Mg. Now How to calculate the actual concentration of Mg in the actual sample?
I think you already have the answer (although there are way too many decimal places):
Consider it this way: Even if the bone sample was pure magnesium,
100 mg ÷ 0.060 L = 1666 mg/L (or ppm). It seems unlikely you will get more than that into the 60 mL solution sampled by the ICPMS.
So I would assume the value you refer to is calculated as the concentration of Mg in the bone ash (9200 ppm or 9200 µg Mg per g of ash). With only 100 mg you have (0.1g x 9200 µg/g = 920 µg Mg in your sample).
If you calculate it forwards:
At 9200 ppm (or µg Mg/g), 100 mg (0.1 g) of bone ash yields 920 µg of Mg.
920 µg dissolved in 60 mL = 15.3 µg/mL (or 15.3 mg/L, or ppm), which seems like a reasonable concentration to measure on the ICPMS.
9200 ppm is 0.92% of the total bone ash composition. Does that seem comparable to other studies?
Matthew Wheal
in other studies the result calculate as gm/100gm ash .and the results were average 30mg /100gm ash . do you know how to calculated??
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