I am designing a novel type of power system capacitor, and a colleague suggested I investigate what effect the induced magnetic fields would have on the device. The device is like an old airgap "butterfly" capacitor which will have charged discs rotating at 60 Hz. Based on some crude calculations, which are attached, I found the force of the magnetic fields to be an exceedingly small fraction of the electric fields such that: F_b/F_e = 3.16E-12; for a 1-meter radius device rotating at 60 Hz. Are these calculations approximately, correct?
I failed to mention that F_b/F_E in these calculations is equal to 2 u e w^2.
If that helps.
In your rough calculations, you considered the induced magnetic field of the rotating charge (on the disc). You'd also consider the external electromagnetic fields and the frequency at which this capacitor will resonate or changed to inductor. Try to draw a circuit model for the equivalent circuit of your capacitor and draw its impedance (Z) versus frequency (w) or Foster diagram, to see how your capacitor is stable. By the way, you can develop such a circuit model , by measurement of Z(w). Ideal (and stable) capacitor will have |Z| = 1/w.C for a wide range of frequencies (w).
Muhammad Hamza El-Saba Thank you for your response; however, I am specifically inquiring about the induced magnetic fields from the displacement currents within the capacitance of the device, such as the equations provided in the attachment. I am familiar with Foster diagrams and they cannot be used to answer this type of question.
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