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Questions related from Dr Muhammad Idrees
The eqs like this x(k+1)=[(x^2 (k))/x(k-1) [1-b/(b^∗ (k) )]]+ b/(b^∗ (k) ) x^∗ (k+1)+(w(k)x(k))/x(k-1) +w(k+1) •OR • •e(k+1)=-(x^2 (k))/x(k-1) [b/α"k" -1]+x^∗ (k+1)[b/α"k"...
01 January 1970 4,163 3 View
