Nakagami channels are used when the received signal has contributions from both diffuse and specular scattering, i.e., the electric field is the sum of a strong component (which is not necessarily line of sight) and several contributions with less amplitude. The m parameter relates the amplitudes of strong and weak components. Rayleigh fading is obtained when m=1. The Nakagami model is in general very similar to a Rician channel, but its pdf has a closed form expression which is simpler to evaluate numerically (it does not contain Bessel functions) and fits better some measurements. There is also an equivalence between the K parameter in the Rician distribution and the m parameter in Nakagami. For a very brief introduction to multipath channels you can see Andrea Goldsmith's book:

http://web.cs.ucdavis.edu/~liu/289I/Material/book-goldsmith.pdf

Or if you need something more especific about Nakagami fading, you can check this physical model:

http://ieeexplore.ieee.org/stamp/stamp.jsp?tp=&arnumber=231886

Why is Nakagami-m fading channel a good in practice in place of Rayleigh fading ? - ResearchGate. Available from: https://www.researchgate.net/post/Why_is_Nakagami-m_fading_channel_a_good_in_practice_in_place_of_Rayleigh_fading [accessed Jan 5, 2016].

It has been acknowledged in recent years that the use of multiple inputs and multiple outputs (MIMO) can potentially provide large spectral efficiency for wireless communications in the presence of multipath fading environments.In most previous

research on MIMO capacity, the channel fading is assumed to be Rayleigh distributed. Of course, the Rayleigh fading model is known to be a reasonable assumption

for the fading encountered in many wireless communications systems. Nevertheless, many measurements campaignsshow that the Nakagami-m distribution provides a much better fitting for the fading channel distribution. In fact, since the Nakagami-m distribution has one more free parameter, it allows for more flexibility. It moreover contains both the Rayleigh distribution (m = 1) and the uniform distribution on

the unit circle (m → ∞) as special (extreme) cases.

Nakagami-m fading channels are generally used to model multiple paths fading. $m$ refers to the fading order.

Nakagami-m fading channels are generally used to model multiple paths fading. $m$ refers to the fading order.

The parameter m is called the 'shape factor' of the Nakagami or the gamma distribution.

In the special case m = 1, Rayleigh fading is recovered, with an exponentially distributed instantaneous power

For m > 1, the fluctuations of the signal strength reduce compared to Rayleigh fading.

thank u Andrea Piroddi 

I want to know theoretical proof like Rayleigh distribution. 

The Nakagami-m distribution is a general, but approximate solution to the random phase problem. The exact solution to this problem involves the knowledge of the distribution and the correlations of all of the partial waves composing the total signal and becomes infeasible due to its complexity. This has been circumvented by Nakagami who, through empirical methods based on field measurements followed by

a curve-fitting process, obtained the approximate distribution. Look at the attached paper.

best regards

The Nakagami-m distribution is a general, but approximate solution to the random phase problem. The exact solution to this problem involves the knowledge of the distribution and the correlations of all of the partial waves composing the total signal and becomes infeasible due to its complexity. This has been circumvented by Nakagami who, through empirical methods based on field measurements followed by

a curve-fitting process, obtained the approximate distribution. Look at the attached paper.

best regards

Nakagami channels are used when the received signal has contributions from both diffuse and specular scattering, i.e., the electric field is the sum of a strong component (which is not necessarily line of sight) and several contributions with less amplitude. The m parameter relates the amplitudes of strong and weak components. Rayleigh fading is obtained when m=1. The Nakagami model is in general very similar to a Rician channel, but its pdf has a closed form expression which is simpler to evaluate numerically (it does not contain Bessel functions) and fits better some measurements. There is also an equivalence between the K parameter in the Rician distribution and the m parameter in Nakagami. For a very brief introduction to multipath channels you can see Andrea Goldsmith's book:

http://web.cs.ucdavis.edu/~liu/289I/Material/book-goldsmith.pdf

Or if you need something more especific about Nakagami fading, you can check this physical model:

http://ieeexplore.ieee.org/stamp/stamp.jsp?tp=&arnumber=231886

Why is Nakagami-m fading channel a good in practice in place of Rayleigh fading ? - ResearchGate. Available from: https://www.researchgate.net/post/Why_is_Nakagami-m_fading_channel_a_good_in_practice_in_place_of_Rayleigh_fading [accessed Jan 5, 2016].

I can compute the average received power in distance d between a sender and a receiver, but I cannot compute the power of a received signal by Nakagami distribution in a receiver?

Do you have any ideas to do that?

what is BER expression for Nakagami fading

BER (Bit Error Rate) Suneela Reddy