There is no time travel. What you see for entanglement Is that the cosmic horizon resolves spin holographically. When A is measured, it’s cosmic horizon resolves A‘s encoding of B‘s spin by shrinking A’s cosmic horizon by one Planck area. Since A and its “guest“ encoding of B are holographically encoded across A’s cosmic horizon, they are always adjacent. Even if A and B are separated by light years, on the cosmic horizon A and A’s encoding of B exist on the horizon within a Planck area of each other. Then when B is measured, A’s horizon encoding of B was spin-locked and measuring B causes A’s cosmic horizon to potentiate a Hawking photon to conserve A’s cosmic horizon shrinkage.

Here is how nature handles entropy.

Delta S Cosmic + Delta S Local = 0.

A’s cosmic horizon shrinks one Planck area so A can resolve‘s B’s spin holographically, -1, and measuring B incites the Hawking photon emission, +1. Spins are opposite so conserve and energy is opposite and so conserves. (S+, E-)A -> (S-, E+)B = 0. Where the first of the entangled pair to be measured is labeled A. Where S+ is the determinant spin, S- subordinate, E- gravity used to correlate A’s spin with B, E+ for Hawking emission. Holographic spin resolution via cosmic horizon shrinkage is what causes “spooky action at a distance“ because matter particle spin is holographically encoded on cosmic horizons. No matter the separation in 3-D space, holographically encoded particles are all adjacent to each other. This is not time travel. You can’t transmit info from the present to the past. Cosmic horizons behave as entropy ledgers.