The amplitude is usually expressed as E the electric field in volts/meter. It can also be expressed as H the magnetic field in amperes/metre.
The electric or magnetic field can be derived from the power density S because S = E2/Z0 =Z0H2 with Z0 being the impedance of free space = sqrt(u0/e0). If it isn't in free space use the impedance of whatever it is in.
E is the rms field, and the instantaneous field for a plane wave travelling in the z direction varies in space and time as real (E sqrt(2) exp(j(wt-kz))), i.e. a sine or cosine wave of height E sqrt(2) with frequency w/2/pi and wavelength 2 pi/k.
see https://courses.lumenlearning.com/suny-physics/chapter/24-4-energy-in-electromagnetic-waves/#:~:text=In%20electromagnetic%20waves%2C%20the%20amplitude,(See%20Figure%201.)&text=where%20c%20is%20the%20speed,in%20W%2Fm2). for instance
Malcolm White,
Many thanks for the explanation and documentation. Regards.
Absolutely! The amplitude of an electromagnetic wave is represented by the maximum value of the electric field or magnetic field in the wave. For a sinusoidal electromagnetic wave, the amplitude (E₀) can be related to the wave's intensity (I) through the formula:
�=12�0��02I=21ε0cE02
Here:
- �I is the intensity of the wave,
- �0ε0 is the permittivity of free space,
- �c is the speed of light in a vacuum,
- �0E0 is the amplitude of the electric field.
If you know the intensity of the wave and the other constants, you can rearrange the formula to solve for the amplitude (�0E0).
The question was asked incorrectly. One needs to know statement of the problem: field source, observation point and environmental properties. Then one needs to solve Maxwell equations.
Employing high frequency simulator also needs some qualification.
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