If the fields (both static and of the wave) are not extremely strong, if the superposition occurs in vacuum, and if the wave does not exchange energy with the means of applying the fields (e. g. photoelectric effect), there will be no distortion.

There is the Faraday effect and the Kerr and Pockels effects, however:  If the (quasi-) static magnetic field is aligned parallel or anti-parallel to the propagation of the wave in a transparent medium, the plane of polarization will be rotated. If an electric field is applied perpendicular to the direction of propagation of the wave in a transparent medium, the refractive index of the medium is effectively changed.

These effects per se do not cause distortion in the sense that harmonics are produced.  But combined with suitable filters, e. g. polarizers, they can be used to modulate the wave; in this process the spectrum of the wave is broadened.

If the fields (both static and of the wave) are not extremely strong, if the superposition occurs in vacuum, and if the wave does not exchange energy with the means of applying the fields (e. g. photoelectric effect), there will be no distortion.

There is the Faraday effect and the Kerr and Pockels effects, however:  If the (quasi-) static magnetic field is aligned parallel or anti-parallel to the propagation of the wave in a transparent medium, the plane of polarization will be rotated. If an electric field is applied perpendicular to the direction of propagation of the wave in a transparent medium, the refractive index of the medium is effectively changed.

These effects per se do not cause distortion in the sense that harmonics are produced.  But combined with suitable filters, e. g. polarizers, they can be used to modulate the wave; in this process the spectrum of the wave is broadened.

Thank you so much "Joerg Fricke", But in an other case,we say that an electromagnetic wave consist of a charge less photon, but how these charge less particle interact with electric and magnetic field?

Hi Muhammad,

I'm not certain if I understand your question correctly but I'll try to answer (in the framework of classical physics):  The electric field and the magnetic field are fields of force, i. e. you can measure their properties (strength, direction) by mechanical means. Charge is by definition the source of electric fields and, if moving, of magnetic fields.  At the same time, the forces effected by electric and magnetic fields are exerted only on charged particles resp. charged bodies.

The primary cause of electromagnetic radiation fields are accelerated charges but the radiation has been separated completely from these charges. Since electromagnetic radiation consists of force fields it exerts forces on charges. Since the radiation is chargeless, no forces can be exerted on the radiation by other electromagnetic fields. So, there is no interaction between radiation and other electric or magnetic fields.

Radiation exerting a force on charge without any reacting force on the radiation sounds like a violation of Newton's third law. However, this violation disappears when we take the momentum of radiation into account: If a charged particle is accelerated by radiation, the radiation loses energy as well as momentum. In terms of photons: If the energy of a photon is transferred to a charged particle, the photon disappears. (For partial transfer of energy, and photon and charged particle acting like billiard balls see Compton effect; but this is beyond classical physics.)

Consider a charged capacitor or a current-carrying coil and a light beam traversing their electric resp. magnetic field in vacuum without illuminating the capacitor or the coil itself: The charges in the capacitor or in the coil are not accelerated by the light. So, the light beam is (or the photons in the light beam are) not affected either.

The situation is different if the wave and the quasi-static field are superimposed in a transparent medium because every medium contains charged particles. 

Thank you so much "Jorge".

Now, my concept is fully cleared.

Photons in free space do interact slightly with each other according to general relativity.  Energy density has the same effect in general relativity as mass does so there will be (usually very small and negligible) gravitation attraction between photons.