how to select the distinct color (namely #303030 hex ) then create new image of the size 305 305 3
Do you intent to segmentate the image based on the color you mention?
As you are not specific here is an answer (in c). You have to iterate through all the input pixels and check if the color matches the one you are looking for:
//begin C
char *pIn = imIn;
char *pOut = mask;
char *pNew;
int count = width*heigh;
imNew = (char*)malloc( count*3*sizeof(char) );
int pix = count;
while( pix--){
char r = *pIn++;
char g = *pIn++;
char b = *pIn++;
if (r == 30 && g == 30 && b == 30 )
*pOut++ = 1;
else
*pOut++ = 0;
}
//Use the mask some else where:
char *pOrig = imIn;
pIn = mask;
pOut = imNew;
pix = count;
char valOut = 255;
while( pix--){
if ( *pIn++ == 1){
*pOut++ = valOut;
pOrig++;
}
else
*pOut++ = pOrig++;
*pOut++ = pOrig++;
*pOut++ = pOrig++;
}
//end c
///////////////////////////////////////////////////////////////
If you are more confortable with Matlab:
%%%%%%%%%%%%%%%%%%%
%BEGIN MATLAB
%some input with color #303030
imIn = imread('peppers.png');
imIn = imIn(1:305,1:305,:);
imIn(150:230,150:230,:)=30;
subplot(131),imshow(imIn), title('imIn');
%find the given color as mask
mask = (imIn(:,:,1) == 30)&(imIn(:,:,2) == 30)&(imIn(:,:,3) == 30);
subplot(132),imshow(mask), title('mask');
%make a new image and set some values using mask
rgbMask(:,:,1) = logical( mask );
rgbMask(:,:,2) = false(size(mask));
rgbMask(:,:,3) = false(size(mask));
imNew = zeros(305,305,3,'uint8');
imNew(rgbMask) = 255;
subplot(133),imshow(imNew), title('imNew');
%END MATLAB
Try this code (after adjusting the variable targetColor for the color you are looking for):
% target color parameter
targetColor = [127 130 33];
% get image
[filename, folder] = uigetfile();
img = imread(fullfile(folder,filename));
% look for match
figure,imshow(img),title('Original image');
for i = 1:3
mask(:,:,i) = img(:,:,i)==targetColor(i);
end
% build boolean mask
mask = mask(:,:,1)&mask(:,:,2)&mask(:,:,3);
figure,imshow(mask),title('Mask');
Be careful as only the pixels perfectly matching the target color will constitute the mask, so the result may be different from what you expect.
Best regards
No, you are not, as it seems from your original question that you are working with HEX number. So, first convert 30 HEX in decimal system and then build the targetColor vector (FYI, #303030 HEX is [48 48 48]).
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