Dear All,
Ni=[8 46 26 106]
N=∑Ni
I want to make this summation step by step in a loop in matlab, just like the basic code below
N(1)=8
N(2)=46
N(3)=26
N(4)=106
FOR I=1 TO 4
TOTAL=TOTAL+N(I)
END
If you help me, I'd be grateful.
Hi Ayhan,
the answer is:
N(1)=8
N(2)=46
N(3)=26
N(4)=106
TOTAL=0
for I=1:4
TOTAL=TOTAL+N(I)
end
Hope this helps!
Best,
Julian
As its name says it, Matlab if much more efficient if you use matrix-like operations instead of low level For loops. It is very powerful if used in the "Matlab way" so I suggest you check the attached primer guide (around page 47).
Hi Ayhan,
the answer is:
N(1)=8
N(2)=46
N(3)=26
N(4)=106
TOTAL=0
for I=1:4
TOTAL=TOTAL+N(I)
end
Hope this helps!
Best,
Julian
A faster way, to avoid the loop as suggested by Bruno and speed up matlab computation in case of large data set would be to use the function 'sum':
N(1)=8
N(2)=46
N(3)=26
N(4)=106
TOT=sum(N)
You can write just two lines:
N=[8 46 26 106];
Total=sum(N)
Or even shorter,
Total=sum([8 46 26 106])
As previously mentioned, avoiding loops in Matlab, if possible, is much better.
Using the built in function sum will make life easier. In your example the input is a vector and this will require one loop and this will be definitely increased to two and three in case of 2D and 3D matrices.
To speed up and write a compact code, you may use the following code:
total=sum(Ni(:)) ;
Good Luck
clc
clear all
N={8 46 26 106};
total=0;
for(i=1:1:length(N))
total=total+N(i);
end
total
Dear All, Thanks for your attention, I have solved the problem by using "cumsum" the function.
Dear Ayhan,
It is great to know that you solved it. However, I guess, all here misunderstood your question as it seemed that you want to calculate the sum which is different from accumulative sum.
Best
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